4/(4x^2-x-24)=7/(7c^2-7c-36)

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Solution for 4/(4x^2-x-24)=7/(7c^2-7c-36) equation: 


D( x )

4*x^2-x-24 = 0

7*c^2-(7*c)-36 = 0

4*x^2-x-24 = 0

4*x^2-x-24 = 0

4*x^2-x-24 = 0

DELTA = (-1)^2-(-24*4*4)

DELTA = 385

DELTA > 0

x = (385^(1/2)+1)/(2*4) or x = (1-385^(1/2))/(2*4)

x = (385^(1/2)+1)/8 or x = (1-385^(1/2))/8

7*c^2-(7*c)-36 = 0

7*c^2-(7*c)-36 = 0

7*c^2-7*c-36 = 0

7*c^2-7*c-36 = 0

x należy do R

x belongs to the empty set

4/(4*x^2-x-24) = 7/(7*c^2-(7*c)-36)

x belongs to the empty set

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